(1) In an abelian group (ab)2 = a2b2" a,b,
Î G
(2) In an abelian group (ab)-1 = a-1b-1" a,b,
Î G
(3) In a group of even order there exists an
element other than identity which is its own
inverse
(4) In an abelian group, every element is its
own inverse.
11.
If 4 sin-1 (x) + cos-1 (x)
= p then x =
(1) 1/3
(2) 2/3
(3) 2
(4) 1/2
12.
If logp x = α,and
logq x = β then the value of logp/q x=
If the coefficients
of (2r + 4)th and (r-2)th terms in the expansion of (1 + x)18
are equal then the value of r is
(1) 6
(2) 8
(3) 3
(4) 5
48.
The value of tan 10 tan 20
....tan 890 is
(1) 1/Ö2
(2) 2
(3) ¥
(4) 1
49.
If A + B + C =
p and cos A = cos B cos C then the
value of cot B cot C =
(1) 1
(2) 1/3
(3) 1/2
(4) 2
50.
From the top of a lighthouse, the
angles of depression of two stations on opposite sides of it a distance a
part are α and β. The height of the lighthouse
is:
(1) a/cot
α + cot β
(2) a / cot
α cot β
(3) a tan
α tan β/tan α + tan β
(4) a cot
α cotβ/cot α + cos β
51.
If y =
Ösin x+
Ö sin x + Ösin
x +..... to infinity then dy/dx =
(1) 2y -1/cos x
(2) y2/cos x
(3) cos x/2y -1
(4) sin x/2y-1
52.
The derivative of tan-1 [
Ö1 + x2 -1/x] with
reference to tan-1 (x):
(1) 1
(2) 1/2
(3) 1/3
(4) 1/4
53.
If f(x) = cos-1
[1-( log x)2/1 + ( log x)2] then f' (e) is
(1) 1/e
(2) Does not exist
(3) 1
(4) 2/e
54.
If y = tan-1 [Ö1
- cos x/1 + cos x] then d2y/dx2 is
(1) 1/2
(2) 1/cos x
(3) 0
(4) 1
55.
If f(m, n) = òp/20cosm cos nx dx and f(m,n) = m/m + n f(m -1, n-1) then f(n,n) =
(1) p/2n
(2) p/4
(3) 1/2 f(m,n)
(4) p/2n+1
56.
The equation x2 + y2
- 2xy -1 = 0 represents:
(1) Two perpendicular straight lines
(2) Hyperbola
(3) A circle
(4) Two parallel straight lines
57.
The given two circles x2 + y2 - 2x + 6y + 6 =0
and x2 + y2 - 5x + 6y + 15 = 0 are
(1) Concentric circles
(2) Intersecting type of circles
(3) Touch each other externally
(4) Touch each other internally
58.
3x - 5y - 8 = 0 is the radical axis of a
coaxial system of circles. If x2 + y2 + 2x - 4y + 7 = 0
is a number of the system, the member of the system through (1, 0) is given
by: